2n^2-995n+10=0

Solution for 2n^2-995n+10=0 equation:

2n^2-995n+10=0

a = 2; b = -995; c = +10;
Δ = b2-4ac
Δ = -9952-4·2·10
Δ = 989945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-995)-\sqrt{989945}}{2*2}=\frac{995-\sqrt{989945}}{4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-995)+\sqrt{989945}}{2*2}=\frac{995+\sqrt{989945}}{4}
$